`bit::matrix` — Convert to a Bit-Vector

We have a method that packs the bit-matrix into a bit-vector.

constexpr bit::vector<Block, Allocator>
to_vector(bool by_rows = true) const;

By default, this returns a bit-vector with all the elements of the bit-matrix stored row by row. If the argument by_rows is set to false the return bit-vector will have the elements of the bit-matrix stored column by column.

Example

#include <bit/bit.h>
int main()
{
1    bit::matrix<> m(4, [](std::size_t i, std::size_t) { return (i)%2; });
2    auto vrow = m.to_vector();
3    auto vcol = m.to_vector(false);
    std::cout << "Original:\n" << m    << '\n';
    std::cout << "By row: "    << vrow << '\n';
    std::cout << "By col: "    << vcol << '\n';
4    std::cout << "From row:\n" << bit::matrix(vrow, 4) << '\n';
5    std::cout << "From col:\n" << bit::matrix(vcol, 4, false) << '\n';
}

1: Construct a bit-matrix with rows that alternate between all zeros and all ones.
2: Pack the bit-matrix in a bit-vector row by row.
3: Pack the bit-matrix in a bit-vector column by column.
4: Reconstitute a bit-matrix from the row-by-row bit-vector.
5: Reconstitute a bit-matrix from the column-by-column bit-vector.

Output

Original:
│0 0 0 0│
│1 1 1 1│
│0 0 0 0│
│1 1 1 1│
By row: [0 0 0 0 1 1 1 1 0 0 0 0 1 1 1 1]
By col: [0 1 0 1 0 1 0 1 0 1 0 1 0 1 0 1]
From row:
│0 0 0 0│
│1 1 1 1│
│0 0 0 0│
│1 1 1 1│
From col:
│0 0 0 0│
│1 1 1 1│
│0 0 0 0│
│1 1 1 1│

See Also